Question on: JAMB Physics - 2017
The velocity ratio of an inclined plane where angle of inclination in θ is
A
Sinθ
B
Cosθ
C
Tanθ
D
\(\frac{1}{\sin \theta}\)
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Correct Option: D
Consider an inclined plane shown below, as the effort moves along OB, the load moves is lifted up through a vertical height AB
V.R = (\frac{\text{distance moved by effort}}{\text{distance moved by load}}) = (\frac{OB}{AB})
But Sinθ = (\frac{opp}{hyp}) = (\frac{AB}{OB})
therefore; = (\frac{OB}{AB}) = (\frac{1}{\sin \theta})
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