The volume of 0 354g of helium at 273 C and 114... - JAMB Physics 2019 Question
The volume of 0.354g of helium at 273°C and 114cm of mercury pressure is 2667cm\(^3\). Calculate the volume
A
2000.25 cm\(^3\)
B
200.025 cm\(^3\)
C
4003.27 cm\(^3\)
D
2010.25 cm\(^3\)
correct option: b
m = 0.354g,
T\(_1\) = 273°C = 273 + 273 = 576K
P\(_1\) = 114cmHg, V\(_1\) = 2667cm\(^3\) at STP
T\(^2\) = 273K, P\(_2\) = 76cmHg, V\(_2\) = ?
But,
| P\(^1\)V\(^1\)
T\(^1\) |
= | P\(^2\)V\(^2\)
T\(^1\) |
| V\(_2\) | = | 114 × 2667 × 273
76 × 576 |
= | 2000.25cm\(^3\) |
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