Question on: JAMB Mathematics - 2003
Three consecutive terms of a geometric progression are given as n-2, n and n=3. Find the common ratio
A
1/4
B
1/2
C
2/3
D
3/2
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Correct Option: D
\(r=\frac{n}{n-2}\hspace{1mm}and\hspace{1mm}r=\frac{n+3}{n}\∴\frac{n}{n-2}=\frac{n+3}{n}\n^2 = n^2 +3n - 2n-6\0=n-6\∴n=6\But\hspace{1mm}r = \frac{n}{n-2}\r=\frac{6}{6-2}\\frac{6}{4}=\frac{3}{2}\)
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