Question on: JAMB Physics - 1997
Three electric cells each of e.m.f 1.5V and internal resistance of 1.0(\Omega) are connected in parallel across an external resistance of (\frac{2}{3})(\Omega). Calculate the value of the current in the resistor
A
0.5 A
B
0.9A
C
1.5A
D
4.5A
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Correct Option: C
E.m.f = 1.5
r = (\frac{1 \times\ 1 \times 1}{(1 \times\ 1) + (1 \times\ 1) + (1 \times\ 1)})
r = (\frac{1}{3})(\Omega)
I = (\frac{E.m.f}{r + R})
I = (\frac{1.5}{\frac{1}{3}\ + \frac{2}{3}})
I = 1.5A
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