Question on: WAEC Physics - 2001
Three identical lamps each power 100W are connected in parallel across a potential difference of 250V. Calculate the current in the circuit
A
7.5A
B
2.5A
C
1.2A
D
0.8A
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Correct Option: C
P = IV
I = \(\frac{P}{V} = \frac{3 \times 100}{250} = 1.2A\)
I = \(\frac{P}{V} = \frac{3 \times 100}{250} = 1.2A\)
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