To arrive on schedule a train is to cover a dis... - WAEC Mathematics 2002 Question
To arrive on schedule, a train is to cover a distance of 60km at 72km/hr. If it starts 10 minutes late, at what speed must it move to arrive on schedule?
A
60km/hr
B
80km/hr
C
90km/hr
D
108km/hr
correct option: c
\(speed = \frac{distance}{time}\
72 = \frac{60}{time}\
t = \frac{60}{72} = \frac{5}{6}hr\)
time lost = 10mis \(= \frac{10}{60}hr = \frac{1}{6}\)
Time required for the journey
\(=\frac{5}{6}-\frac{1}{6} = \frac{2}{3}\
speed \hspace{1mm}=60 \div \frac{2}{3} = 90km/hr\)
72 = \frac{60}{time}\
t = \frac{60}{72} = \frac{5}{6}hr\)
time lost = 10mis \(= \frac{10}{60}hr = \frac{1}{6}\)
Time required for the journey
\(=\frac{5}{6}-\frac{1}{6} = \frac{2}{3}\
speed \hspace{1mm}=60 \div \frac{2}{3} = 90km/hr\)
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