Question on: WAEC Mathematics - 2002
To arrive on schedule, a train is to cover a distance of 60km at 72km/hr. If it starts 10 minutes late, at what speed must it move to arrive on schedule?
A
60km/hr
B
80km/hr
C
90km/hr
D
108km/hr
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Correct Option: C
(speed = \frac{distance}{time}<br />
72 = \frac{60}{time}<br />
t = \frac{60}{72} = \frac{5}{6}hr)
time lost = 10mis (= \frac{10}{60}hr = \frac{1}{6})
Time required for the journey
(=\frac{5}{6}-\frac{1}{6} = \frac{2}{3}<br />
speed \hspace{1mm}=60 \div \frac{2}{3} = 90km/hr)
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