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TQ is tangent to circle XYTR lt YXT 32o RTQ 40o... - JAMB Mathematics 1998 Question

TQ is tangent to circle XYTR, < YXT = 32o, RTQ = 40o. fIND < YTR
A
108o
B
121o
C
140o
D
148o
correct option: a
< TWR = < QTR = 40o (alternate segment)

< TWR = < TXR = 40o(Angles in the same segments)
< YXR = 40o + 32o = 72o

< YXR + < YTR = 180o(Supplementary)

72o + < YTR = 180o

< YTR = 180o - 72o

= 108o
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