Question on: JAMB Mathematics - 1998

TQ is tangent to circle XYTR, < YXT = 32^o, RTQ = 40^o. fIND < YTR

108^o

121^o

140^o

148^o

Ask EduPadi AI for a detailed answer

Correct Option: A

< TWR = < QTR = 40^o (alternate segment)

< TWR = < TXR = 40^o(Angles in the same segments)
< YXR = 40^o + 32^o = 72^o

< YXR + < YTR = 180^o(Supplementary)

72^o + < YTR = 180^o

< YTR = 180^o - 72^o

= 108^o

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