TQ is tangent to circle XYTR lt YXT 32o RTQ 40o... - JAMB Mathematics 1998 Question

TQ is tangent to circle XYTR, < YXT = 32^o, RTQ = 40^o. fIND < YTR

< TWR = < QTR = 40^o (alternate segment)

< TWR = < TXR = 40^o(Angles in the same segments)

< YXR = 40^o + 32^o = 72^o

< YXR + < YTR = 180^o(Supplementary)

72^o + < YTR = 180^o

< YTR = 180^o - 72^o

= 108^o