Question on: JAMB Physics - 2010
Two inductors of inductances 5 mll and 15 mll are connected in series and a current of 5A flows through them. the total energy stored in the inductor is
A
500.0J
B
250.0J
C
62.5J
D
50.0J
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Correct Option: E
Correct Answer: Option E
Total inductance,L = L1 + L2 = m
15 + 5 = 20mH = (20)H/1000
1 = 5A
Energy of inductor, (1)/2 L I2
= (1)/2 X (20)/1000 X 5-2
= 0.25 J
15 + 5 = 20mH = (20)H/1000
1 = 5A
Energy of inductor, (1)/2 L I2
= (1)/2 X (20)/1000 X 5-2
= 0.25 J
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