Question on: JAMB Physics - 1995
Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?
A
4.8 Vm-1
B
75.0Vm-1
C
4800.0Vm-1
D
75000.0Vm-1
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Correct Option: D
E = \(\frac{voltage}{distance}\)
= \(\frac{600}{8 \times 10^2}\)
= 75000.0Vm-1
= \(\frac{600}{8 \times 10^2}\)
= 75000.0Vm-1
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