Two point charges q1 2 C and q2 -4 C are placed... - SS2 Physics Electromagnetism Question
Two point charges, q1 = +2 μC and q2 = -4 μC, are placed 10 cm apart. What is the electric field at a point located 5 cm from q1 and 5 cm from q2? (Assume vacuum permittivity is ε0 = 8.85 x 10-12 C2/N m2)
Electric field due to q1: E1 = (k x |q1|) / r2
= (9 x 109 N m2/C2 x 2 x 10-6 C) / (0.05 m)2
= 1.8 x 10^6 N/C
Electric field due to q2: E2 = (k x |q2|) / r2
= (9 x 109 N m2/C2 x 4 x 10-6 C) / (0.05 m)2
= 3.6 x 106 N/C
Total electric field at the point: Etotal = E1 + E2 = 1.8 x 106 N/C + 3.6 x 106 N/C = 5.4 x 106
The direction of the electric field will be away from q1 and towards q2.
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