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Use Hess s Law to calculate the enthalpy change... - SS3 Chemistry Chemical Thermodynamics Question

Use Hess's Law to calculate the enthalpy change for the reaction:

2CO(g) + O2(g) → 2CO2(g)

given the following thermochemical equations:

1. C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ/mol

2. C(s) + 1/2O2(g) → CO(g) ΔH = -111.0 kJ/mol

To find the enthalpy change for the target reaction, we can manipulate the given equations and add them to obtain the desired equation:

1. C(s) + O2(g) → CO2(g) ΔH = -393.5 kJ/mol (Given)

2. 2CO(g) + O2(g) → 2CO2(g) (Multiply Equation 2 by 2)

Now, to make the coefficients of CO2 match in both equations, we can reverse Equation 1:

3. CO2(g) → C(s) + O2(g) ΔH = +393.5 kJ/mol (Reverse Equation 1)

Next, we can add equations 2 and 3 to get the target reaction:

4. 2CO(g) + O2(g) + CO2(g) → 2CO2(g) + C(s) + O2(g)

Now, add the enthalpy changes of the equations to find the enthalpy change for the target reaction:

ΔHtarget = ΔH2 + ΔH3

ΔHtarget = 0 kJ/mol (Since the products on the right side are the same as the reactants on the left side)

Therefore, the enthalpy change for the reaction: 2CO(g) + O2(g) → 2CO2(g) is 0 kJ/mol.

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