Question on: WAEC Physics - 2011
Using the circuit diagram above. Calculate the total charge in the circuit
A
80\(\mu C\)
B
35\(\mu C\)
C
20\(\mu C\)
D
16\(\mu C\)
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Correct Option: D
C - (C_1 + C_2 = 2 + 6 = \mu F)
(\frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_1} + \frac{1}{C_2} = \frac{1}{8} + \frac{1}{2})
C = (\frac{8}{5 \mu F})
Q = CV
= (\frac{8}{5} \times 10 = 16\mu C)
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