Question on: WAEC Physics - 1991
Using the data in the circuit illustrated above, calculate the value of R
A
0.02\(\Omega\)
B
0.05\(\Omega\)
C
5.00\(\Omega\)
D
20.00\(\Omega\)
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Correct Option: E
R = \(\frac{V}{T} = \frac{2v}{40 \times 10^{-3}}\)
= 50.00\(\Omega\)
= 50.00\(\Omega\)
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