Question on: WAEC Physics - 2005
Water falls through a height of 50m. Determine the temperature rise at the bottom of the fall. [Neglect energy losses. Specific heat capacity of water = 4200Jkg-1 K-1, g = 10ms2]
A
0.119oC
B
0.840oC
C
1.190oC
D
8.400oC
Ask EduPadi AI for a detailed answer
Correct Option: A
mgh = mc\(\theta\)
\(\theta = \frac{gh}{c} = \frac{10 \times 50}{4200}\)
= 0.119oC
\(\theta = \frac{gh}{c} = \frac{10 \times 50}{4200}\)
= 0.119oC
Add your answer
Please share this, thanks!
No responses