Question on: WAEC Physics - 2002
Water of mass 120g at 50oC is added to 20og of water at 10oC and the mixture is well stirred. Calculate the temperature of the mixture. [Neglect heat losses to the surrounding]
A
60oC
B
40oC
C
25oC
D
10oC
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Correct Option: C
120 x 4.2(50 - \(\theta\)) = 200 x 4.2(\(\theta\) - 10)
\(\theta = \frac{33600}{1344} = 25^oC\)
\(\theta = \frac{33600}{1344} = 25^oC\)
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