Question on: JAMB Chemistry - 2001
What current in amperes will deposit 2.7g of aluminium in 2 hours?
[Al = 27, F = 96 500 C mol-1]
A
32
B
8
C
4
D
16
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Correct Option: C
Al3+ + 3e → Al
3 * 96500 → 27
I = 3600 * 2 → 27
I = (2.7/27) * ((3 * 96500)/(3600 * 2))
= 4.025 ≈ 4
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