What is the locus of point that is equidistant ... - JAMB Mathematics 2010 Question
What is the locus of point that is equidistant from points P(1,3) and Q(3,5)?
A
y = -χ + 6
B
y = -χ - 6
C
y = χ + 6
D
y = χ - 6
correct option: a
Locus of a point equidistant from two fixed points is the perpendicular bisector of the straight line joining the points Gradients of PQ = (5-3 / 3-1) = 2/2 = 1
Gradient bisector = -1
Equation of perpendicular bisector
y - y1 = m(χ - χ1
y - 4 = -χ + 2
y = -χ + 6
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