Question on: JAMB Mathematics - 2007
What is the mean deviation 0f 3, 5, 8, 11, 12 and 21?
A
37
B
60
C
10
D
4.7
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Correct Option: D
mean(\(\bar{x}\)) = \(\frac{\sum x}{n}\)
= \(\frac{7 + 5 + 2 + 1 + 2 + 11}{6}\) = 10
M.D = \(\frac{7 + 5 + 2 + 1 + 2 + 11}{6}\)
= \(\frac{28}{6}\)
= 4.7
= \(\frac{7 + 5 + 2 + 1 + 2 + 11}{6}\) = 10
M.D = \(\frac{7 + 5 + 2 + 1 + 2 + 11}{6}\)
= \(\frac{28}{6}\)
= 4.7
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