Question on: JAMB Mathematics - 2008
What is the mean of the data t, 2t-1, t-2, 2t-1, 4t and 2t+2?
A
2t
B
2t-1
C
2/3t+1
D
2t-1/3
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Correct Option: D
(Mean = \frac{t+2t-1+t-2+2t-14t+2t+2}{6}\
Mean = \frac{12t-2}{6}\
=\frac{2(6t-1)}{6}\
=\frac{6t-1}{3}\
=\frac{6t}{3}- \frac{1}{3}\
=2t-\frac{1}{3})
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