What is the molality of a solution if 120 grams... - SS1 Chemistry Solutions and Concentration Question

Step 1: Convert the given mass of glucose to moles.

Molar mass of glucose (C6H12O6)

= (6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol)

= 180.18 g/mol

Number of moles of glucose = Mass of glucose / Molar mass of glucose

= 120 g / 180.18 g/mol

≈ 0.666 mol

 

Step 2: Convert the given mass of water to kilograms.

Mass of water = 500 g = 500/1000 kg = 0.5 kg

 

Step 3: Calculate molality using the formula:

Molality (m) = Number of moles of solute / Mass of solvent (in kg)

= 0.666 mol / 0.5 kg

= 1.332 m

The molality of the solution is 1.332 m.