What is the nth term of the progression 27 9 3 - JAMB Mathematics 1991 Question
What is the nth term of the progression 27, 9, 3,......?
A
27\(\frac{1}{3}\) n - 1
B
3n + 2
C
27 + 18(n - 1)
D
27 + 6(n - 1)
correct option: a
Given 27, 9, 3,......this is a G.P
r = \(\frac{9}{27}\)
= \(\frac{1}{3}\)
T = arn - 1
= 27\(\frac{1}{3}\) n - 1
r = \(\frac{9}{27}\)
= \(\frac{1}{3}\)
T = arn - 1
= 27\(\frac{1}{3}\) n - 1
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