What is the perpendicular distance of a point 2... - JAMB Mathematics 1992 Question
What is the perpendicular distance of a point (2, 3) from the line 2x - 4y + 3 = 0?
A
\(\frac{\sqrt{5}}{2}\)
B
\(\frac{\sqrt{5}}{20}\)
C
\(\frac{5}{\sqrt{13}}\)
D
6
correct option: a
2x - 4y + 3 = 0
Required distance = (\frac{(2 \times 2) + 3(-4) + 3}{\sqrt{2^2} + (-4)^2})
= (\frac{4 - 12 + 3}{\sqrt{20}})
= (\frac{-5}{-2\sqrt{5}}}
= -{\frac{\sqrt{5}{2})
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