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What is the perpendicular distance of a point 2... - JAMB Mathematics 1992 Question

What is the perpendicular distance of a point (2, 3) from the line 2x - 4y + 3 = 0?
A
\(\frac{\sqrt{5}}{2}\)
B
\(\frac{\sqrt{5}}{20}\)
C
\(\frac{5}{\sqrt{13}}\)
D
6
correct option: a

2x - 4y + 3 = 0

Required distance = (\frac{(2 \times 2) + 3(-4) + 3}{\sqrt{2^2} + (-4)^2})

= (\frac{4 - 12 + 3}{\sqrt{20}})

= (\frac{-5}{-2\sqrt{5}}}

= -{\frac{\sqrt{5}{2})

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