What is the probability that an integer x \((1 \leq x \leq 25)\) chosen at random is divisible by both 2 and 3?
Correct Option:
C
\((1 \leq x \leq 25)\) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25}
Number N of x divisible by both 2 and 3 is 4.
n(\(\varepsilon\)) = 25
= \(\frac{N}{n(\varepsilon)}\)
= \(\frac{4}{25}\)
Number N of x divisible by both 2 and 3 is 4.
n(\(\varepsilon\)) = 25
= \(\frac{N}{n(\varepsilon)}\)
= \(\frac{4}{25}\)