Question on: WAEC Mathematics - 1993
What is the probability that the total sum of seven would appear in toss of a fair die?
A
5/36
B
1/6
C
7/36
D
5/6
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Correct Option: B
No of possible outcome = 36
Required outcome (R) = {(1, 6), (6, 1), (2, 5), (5, 2), (3, 4), (4, 3)}
n(R) = \(\frac{6}{36}\)
= \(\frac{1}{6}\)
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