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What is the smaller value of x for which x\(^2\) - 3x + 2= 0?

index-0

1

index-1

2

index-2

3

index-3

4

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Correct Answer: A

x\(^2\) - 3x + 2 = 0

x\(^2\) - 2x - x + 2 = 0

x(x - 2) - 1(x - 2) = 0

(x - 2)(x - 1) = 0

x = 1 or 2. The smaller value of x = 1.