Question on: SS1 Mathematics - Surafce Area And Volume Of Solid Shapes

\(slant\ height,\ s = \sqrt{h^{2} + r^{2}} = \ \sqrt{8^{2} + 3^{2}} = \ \sqrt{64 + 9} = \ \sqrt{73} = 8.5cm\)

\(total\ surface\ area\ = \pi rs + \pi r^{2}\)

\(total\ surface\ area\ = (\frac{22}{7})(3)(8.5) + (\frac{22}{7}){(3)}^{2}\)

\(= 80.14 + 28.29 = \ 108.43{cm}^{2}\)

\(the\ volume\ of\ a\ cone = \ \frac{1}{3}{\pi r}^{2}h\)

\(the\ volume\ of\ a\ cone = \ \frac{1}{3}{\left( \frac{22}{7} \right)(3)}^{2}(8)\)

t\(he\ volume\ of\ a\ cone = \ 75.43{cm}^{3}\)