Which of the following is equal to \(\frac{72}{125}\)
index-0
\( \frac{2^3 \times 3^2}{5^3} \)
index-1
\( \frac{2^4 \times 3}{5^3} \)
index-2
\( \frac{2^3 \times 3}{5^3} \)
index-3
\( \frac{2^4 \times 3}{5^5} \)
Correct Answer:
A
\(\frac{72}{125} = \frac{8 \times 9}{5 \times 5 \times 5}\)
= \(\frac{2^3 \times 3^2}{5^3}\)