You need to prepare 250 mL of a 0 5 M sodium hy... - SS1 Chemistry Solutions and Concentration Question

Using the same dilution equation:

 

C1V1 = C2V2

 

Where:

C1 = initial concentration (2 M)

V1 = initial volume (unknown)

C2 = final concentration (0.5 M)

V2 = final volume (250 mL)

 

Rearranging the equation, we have:

 

V1 = (C2V2) / C1

 

V1 = (0.5 M x 250 mL) / 2 M

V1 = 62.5 mL

 

To prepare the 0.5 M NaOH solution, you would measure 62.5 mL of the 2 M NaOH stock solution and then add enough solvent to make the total volume 250 mL.

Question:

You have a 1 L solution of glucose with a concentration of 0.4 M. How would you prepare 500 mL of a 0.1 M glucose solution through dilution?

Answer:

Using the dilution equation:

 

C1V1 = C2V2

 

Where:

C1 = initial concentration (0.4 M)

V1 = initial volume (1 L or 1000 mL)

C2 = final concentration (0.1 M)

V2 = final volume (500 mL)

 

Rearranging the equation, we have:

 

V1 = (C2V2) / C1

 

V1 = (0.1 M x 500 mL) / 0.4 M

V1 = 125 mL

 

To prepare the 0.1 M glucose solution, you would measure 125 mL of the 0.4 M glucose solution and then add enough solvent to make the total volume 500 mL.