1991 - JAMB Mathematics Past Questions and Answers - page 5
41
From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point Y. Find the bearing of Y from X.
A
0.30o
B
045o
C
060o
D
090o
correct option: c
tan \(\theta\) = \(\frac{60\sqrt{3}}{60}\) = \(\sqrt{3}\)
\(\theta\) = tan \(\frac{1}{3}\) = 60o
Bearing of y from x = 060o
Users' Answers & Comments\(\theta\) = tan \(\frac{1}{3}\) = 60o
Bearing of y from x = 060o
42
Find the total area of the surface of a solid cylinder whose base radius is 4cm and height is 5cm
A
56\(\pi\) cm2
B
72\(\pi\) cm2
C
96\(\pi\) cm2
D
192\(\pi\) cm2
correct option: b
Users' Answers & Comments43
3% of a family's income is spent on electricity, 58% on food, 20% on transport, 11% on education and 7% on extended family. The angles subtended at the centre of the pie chart under education and food are respectively
A
76.8o and 25.2o
B
10.8o and 224.6o
C
112.4o and 72.0o
D
39.6o and 212.4o
correct option: d
Users' Answers & Comments44
Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result
\(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\)
The mean and the median of the distribution are respectively
\(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\)
The mean and the median of the distribution are respectively
A
6.7, 6
B
7.6, 5
C
5.7, 87
D
34, 6
correct option: a
Users' Answers & Comments45
Fifty boxes each of 50 bolts were inspected for the number which were defective. The following was the result
\(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\)
Find the percentage of boxes containing at least 5 defective bolts each
\(\begin{array}{c|c} \text{No. defective per box} & 4 & 5 & 6 & 7 & 8 & 9 \ \hline \text{No. of boxes} & 2 & 7 & 17 & 10 & 8 & 6\end{array}\)
Find the percentage of boxes containing at least 5 defective bolts each
A
96
B
94
C
92
D
90
correct option: a
% of boxes containing at least 5 defective bolts each
= \(\frac{7 + 17 + 10 + 8 + 6}{50}\)
= \(\frac{48}{50}\) x \(\frac{100}{1}\)
= 96%
Users' Answers & Comments= \(\frac{7 + 17 + 10 + 8 + 6}{50}\)
= \(\frac{48}{50}\) x \(\frac{100}{1}\)
= 96%
46
A crate of soft drinks contains 10 bottles of Coca-cola, 8 of Fanta and 6 of sprite. If one bottle is selected at random, what is the probability that it is NOT a Cocacola bottle?
A
\(\frac{5}{12}\)
B
\(\frac{1}{3}\)
C
\(\frac{3}{4}\)
D
\(\frac{7}{24}\)
correct option: d
Coca-cola = 10 bottles, Fanta = 8 bottles
Sprite = 6 bottles, Total = 24
P(cola-cola) = \(\frac{10}{24}\)
P(not coca-cola) = 1 - \(\frac{10}{24}\)
\(\frac{24 - 10}{24}\) = \(\frac{14}{24}\)
= \(\frac{7}{24}\)
Users' Answers & CommentsSprite = 6 bottles, Total = 24
P(cola-cola) = \(\frac{10}{24}\)
P(not coca-cola) = 1 - \(\frac{10}{24}\)
\(\frac{24 - 10}{24}\) = \(\frac{14}{24}\)
= \(\frac{7}{24}\)
47
A
130o
B
110o
C
100o
D
90o
correct option: a
Users' Answers & Comments48
A
7.3, 5.9
B
7.7, 12.5
C
12.5, 7.7
D
5.9, 7.3
correct option: c
\(\frac{PQ}{PN} = \frac{PM}{PR} = \frac{QM}{NR}\)
\(\frac{4.8}{12} = \frac{5}{PR}\)
PR = \(\frac{5 \times 12}{4.8} = \frac{50}{4}\)
= 12.5
\(\frac{PQ}{PN} = \frac{PM}{PT} = \frac{TM}{NT}\)
\(\frac{PT}{12} = \frac{5}{PR}\)
PT2 = 60
PT = \(\sqrt{60}\)
= 7.746
= 7.7
Users' Answers & Comments\(\frac{4.8}{12} = \frac{5}{PR}\)
PR = \(\frac{5 \times 12}{4.8} = \frac{50}{4}\)
= 12.5
\(\frac{PQ}{PN} = \frac{PM}{PT} = \frac{TM}{NT}\)
\(\frac{PT}{12} = \frac{5}{PR}\)
PT2 = 60
PT = \(\sqrt{60}\)
= 7.746
= 7.7