2006 - JAMB Mathematics Past Questions and Answers - page 5

Cost of removing a 6m² room = N540

Cost of renovating a 1m² room = 540 / 6

Cost of removing a 9m² room

= (540 / 6) * 9

= N810

Let the positive integers be 1, 2, ,3, 4, .....n

∴ a = 1, d = 1 and n = n

Sn = ⁿ/₂(2a + (n-1)d)

= ⁿ/₂ (2 + n – 1)

= ¹/₂n(n + 1)

T = 2 π √¹/_g
^T/_2π = √¹/_g

(^T/_2π)² = (√¹/_g)^2
T2/_4π² = ¹/_g

T² x g = 4π² x l

G = (4π² x l) / T²

y = x² - x - 12

= (x - 4)(x - 3)

∴ x = 4 or x = -3

-3 < x < 4

But y ( \geq ) 0

∴ -3 < x ( \leq ) 4

3, -6, +12, -24

a = 3, r = -2

(8n = \frac{a(1-r^n)}{1-r}\

∴1-2^8 = \frac{3(1-(-2^{n-1}))}{1-(-2)}\

1-2^8 = \frac{3(1-(-2^{n-1}))}{3})

1-2⁸ = 1-(-2)^n-1

-2⁸ = -2^n-1

8 = n-1

n = 9

(tan (\theta) = (\frac{opp}{adj}))

|AB|² = 5² + 4² (\to) |AB|² = 41

(\to) AB = (\sqrt{41}) sin²(\theta) - cos²(\theta)

(\to) (\frac{5^2}{\sqrt{41}}) - ((\frac{4}{\sqrt{41}}^2)) = (\frac{25}{41}) - (\frac{16}{41})

= ((\frac{9}{41}))

PN = NQ

1 + q + 5 + 2q = 3 + 2 + 3 + 4

6 + 3q = 12 (\to) 3q = 12 - 6 = 6

q = 2

2p x 2 + 8 x 1 = 24

(\to) 4p = 24 - 8 = 16, p = 4

3 x 1 + -5q x 2 = -17

(\to) -10q = -17 - 3

-10q = -20

q = 2