2006 - JAMB Mathematics Past Questions and Answers - page 7
61
A
90cm2
B
89cm2
C
80cm2
D
70cm2
correct option: a
Area of PQRS = length x breath(7 x 10)cm2 = 70
Area of semi-circle \(\frac{1}{2} \pi r^2 = \frac{1}{2} \times \frac{22}{7} \times \frac{7}{2}\)
= 19.5cm2 = 20cm2(appr.)
Area of the figure = (70 + 20)cm2
= 90cm2
Users' Answers & CommentsArea of semi-circle \(\frac{1}{2} \pi r^2 = \frac{1}{2} \times \frac{22}{7} \times \frac{7}{2}\)
= 19.5cm2 = 20cm2(appr.)
Area of the figure = (70 + 20)cm2
= 90cm2
62
A
50o
B
80o
C
80cm2
D
100o
correct option: d
< QRS = 30o(corresponding < ), < QSR = 50o
< SQR = 180o - (30 + 50)o (Sum of < S in a \(\bigtriangleup\))
180o - 80o = 100o
Users' Answers & Comments< SQR = 180o - (30 + 50)o (Sum of < S in a \(\bigtriangleup\))
180o - 80o = 100o
63
A
35o
B
55o
C
25o
D
45o
correct option: b
Construction RQ
< PRQ = 90o(amgle substended at the circumfernce of a circle by diameter). Also in figure PQRS
< PQS + PSQ = 180(supplementary angle)
< PQS = 180 - 145 = 35
In \(\bigtriangleup\)PRQ x = 180 - 935 = 90)
x = 55
Users' Answers & Comments< PRQ = 90o(amgle substended at the circumfernce of a circle by diameter). Also in figure PQRS
< PQS + PSQ = 180(supplementary angle)
< PQS = 180 - 145 = 35
In \(\bigtriangleup\)PRQ x = 180 - 935 = 90)
x = 55
64
A
10 \(\sqrt{3}\)cm
B
10cm
C
45cm
D
14cm
correct option: d
Draw a line perpendicular to |SR| to form |PT| in \(\bigtriangleup\) PST, cos 60 = \(\frac{|ST|}{8}\(
|PT| = 8 cos 6 = 4cm
Since |TR| = |PQ|
SR = ST + TR
= (4 + 10)cm
= 14cm
Users' Answers & Comments|PT| = 8 cos 6 = 4cm
Since |TR| = |PQ|
SR = ST + TR
= (4 + 10)cm
= 14cm
65
A
50o
B
40o
C
55o
D
45o
correct option: d
Reflex of < 260 = 360 - 260
= 10(angle at a point0
x = 100 - 55 = 45o
Users' Answers & Comments= 10(angle at a point0
x = 100 - 55 = 45o
66
A
y + x \(\leq\) 4, y \(\geq\) x
B
y \(\leq\) 0, y \(\leq\) x and y + x \(\geq\) 4
C
y \(\geq\) x, y + x \(\geq\) 4 and y \(\leq\) 0
D
y \(\geq\) x, y + x \(\geq\) 4
correct option: c
Users' Answers & Comments67
The pie chart above shows the expenditure of a family whose income is N30.000. If the expenditure on food is twice that on housing and that on school fees is twice that on transport, how much does the family spend on food?
A
N28,000
B
N12,500
C
N15,000
D
N25,000
correct option: b
school fees is 90o
Transport = 45o
Housing and food = 360 - (90 + 45) = 225
food \(\frac{2}{3} \times 225 = 150\)
expenses on food = \(\frac{150}{360} \times 30000\)
= N12500
Users' Answers & CommentsTransport = 45o
Housing and food = 360 - (90 + 45) = 225
food \(\frac{2}{3} \times 225 = 150\)
expenses on food = \(\frac{150}{360} \times 30000\)
= N12500
68
The response of 160 pupils in a school asked to indicate their favourite subjects is given in the bar chart above. What percentage of the pupils have English English and Health education as the their favourite subjects?
A
55%
B
52%
C
36%
D
22%
correct option: a
(\(\frac{52}{160} = \frac{36}{160}\))% = \(\frac{88}{160}\)%
= 55%
Users' Answers & Comments= 55%