2007 - JAMB Mathematics Past Questions and Answers - page 4

M + L = 28,

M : L = 600 : 800

= 3 : 4

(\frac{M}{L}) = (\frac{3}{4}) (\to) M = (\frac{3}{4})L

(\frac{3}{4})L + L = 28

(\frac{7L}{4}) = 28

L = (\frac{4 \times 28}{7})

= 16

x₁₀ = 1214 ₅, 1 x 5³ + 2 x 5² + 1 x 5¹ + 4 x 5^o

= 125 + 50 + 5 + 4 184¹⁰

x = 184

log₁₀ 12.5 = log₁₀(\frac{25}{2})

= log₁₀(\frac{100}{8}) = log₁₀ 100 - log₁₀8

= log₁₀ 10² - log₁₀2

= 2log₁₀ 10 - 3log₁₀²

= 2 - 3x

Total fruits 6 + 11 + 13 = 30,

prob. (Grape) = (\frac{6}{30})

prob. (Banana) = (\frac{11}{30})

= (\frac{11}{30}) + (\frac{6}{30}) = (\frac{17}{30})

No. of students that made the trip

= 2 + 3 = 5 = 6 = 8 = 4 + 1 = 29

The roots of the graph are -2, -1 and 1

y = (x + 2)(x + 1)(x - 1) = (x + 2)(x² - 1)

= x³ + 2x² - x - 2

Arrange in ascending order

2, 5, 5, 6, 6, ,6, 6, 8, 8

Position of median = ^N/₂ = ⁸/₂ = 4th and 5th

∴Median = (6+6) / 2 = ¹²/₂ = 6

Mode the item that repeat itself most = 6

∴Product of modal and median number = 6 x 6 = 36

Number of grapes = 6

Number of banana = 11

Number of oranges = 13

Total = 30

P(Grape) = ⁶/₃₀, P(Banana) = ¹¹/₃₀

P(Orange) = ¹³/₃₀

∴P(Either grape or banana) = ⁶/₃₀ + ¹¹/₃₀

= ¹⁷/₃₀

Number of itineraries = ⁷P₄

=(\frac{7!}{(7-4)!}\

=\frac{7!}{3!}\

=\frac{7 \times 6 \times 5 \times 4 \times 3!}{3!}\

=840)