2007 - JAMB Mathematics Past Questions and Answers - page 3

d = (\sqrt{\frac{42W}{5L}}), square both sides

= d² = (\frac{42W}{5L})

cross multiply: 5d²L = 42W

divide both sides by 5d²

L = (\frac{42W}{5d^2})

T₁ = (\frac{3}{2}) = (\frac{5}{2}) - 1

T₂ = 3 = 5 - 3

T₃ = 7 = 10 - 3 = 5.2 - 3

T₄ = 16 = 20 - 4 = 5.2² - 4

T₅ = 35 = 40 - 5 = 5.2³ - 5

T₆ = 74 = 80 - 6 = 5.2⁴ - 6

Tn = 5.2^{n - 2} - n

(\begin{pmatrix} 3 & -2 \ -7 & 5\end{pmatrix}) + 2(\begin{pmatrix} -2 & 4 \ 3 & -1\end{pmatrix}) = (\begin{pmatrix} 3 & -2 \ -7 & 5\end{pmatrix}) + (\begin{pmatrix} -4 & 8 \ 6 & -2\end{pmatrix})

= (\begin{pmatrix} 3 & -4 \ -7 & 6\end{pmatrix}) + 2(\begin{pmatrix} -2 & 8 \ 5 & -2\end{pmatrix})

= (\begin{pmatrix}-1 & 6 \ -1 & 3\end{pmatrix})

p = {1, 3, 5, 7, 9, 11}, Q = {2, 4, 6, 8, 10, 12}

p ∩ Q = (\phi)

(\frac{3}{5}) (\div) ((\frac{2}{7}) x (\frac{4}{3}) (\div) (\frac{4}{9})) = (\frac{2}{3}) (\div) ((\frac{2}{7}) x (\frac{4}{3}) x (\frac{9}{4}))

= (\frac{3}{5}) (\div) (\frac{6}{7})

= (\frac{3}{5}) x (\frac{7}{6})

= (\frac{7}{10})

Let the cost price be C. For the profit of 5%, selling price = 105% C = N60,000

therefore C = (\frac{100}{105}) x N60,000

For a profit of 26%, the selling price = 126%C

= (\frac{126}{100})C x (\frac{100}{105}) x N60,000

= N72,000

2(3^{2x - 1}) = 162, 3^{2x - 1} = 81

= 3⁴

2x - 1 = 4 , 2x = 5

x = (\frac{5}{2})

1011²₂ - 101²₂ = (1011 - 101)₂ (1011 + 101)₄

= 110₂ x 10000₂

= 1100000₂

(\sqrt{12} - \sqrt{147}) + y(\sqrt{3}) = 0

(\sqrt{4 \times 3 } - \sqrt{49 \times 3}) + y(\sqrt{3}) = 0

y - 5 = 0

y = 5

(\frac{(0.5625)^2 - (0.4375)^2}{0.04}) = (\frac{(0.5625 - 0.4375)(0.5625 - 0.4375)}{0.04})

= (\frac{0.1250 \times 1}{0.04})

= (\frac{12.50}{0.04})