2014 - JAMB Mathematics Past Questions and Answers - page 1

SP = Nx

CP = N60,000

Percentage loss = 15%

Using percentage loss...

(\frac{CP - SP}{CP} = \text{100%})

(\text{15%} = \frac{60000 - x}{60000} \times \text{100%})

(\text{15%} \times 60000 = (60000 - x)\text{100%})

(60000 - x = \frac{\text{15%} \times 60000}{\text{100%}})

60000 - x = 3 x 3000

60000 -x = 9000

x = 60000 - 9000

x = N51,000

0.00043 x 2000

= 43 x 10^-5 x 2 x 10³

= 43 x 2 x 10^-5+3

= 86 x 10^-2

= 8.6 x 10¹ x 10^-2

= 8.6 x 10^-1

Let;

M = Man monthly net earnings

Then;

(\text{N4500} = \frac{\text{10%}}{\text{100%}} \times M )

(M = \frac{\text{N4500} \times \text{100%}}{\text{10%}} )

M = N45,000

If log 7.5 = 0.8751

Then 2log75 + log750

= 2(1.8751) + 2.8751

= 3.7502 + 2.8751

= 6.6253

8x^-2 = 2/25

x^-2 = 2/25 x 1/8

x^-2 = 2/200

x^-2 = 1/100

1/x² = 1/100

x² = 100

x = 10

(= \frac{2\sqrt{2} - \sqrt{3}}{\sqrt{2} + \sqrt{3}} \times \frac{\sqrt{2} - \sqrt{3}}{\sqrt{2} + \sqrt{3}})

(= \frac{2\sqrt{2}(\sqrt{2}) + (2\sqrt{2})(-\sqrt{3})-\sqrt{3}(\sqrt{2})-\sqrt{3}(-\sqrt{3})}{(\sqrt{2})^2-(\sqrt{3})^2})

(= \frac{2 \times 2 - 2\sqrt{6} - \sqrt{6} + 3}{2 - 3})

(= \frac{4 - 3\sqrt{6} + 3}{-1})

(= \frac{7 - 3\sqrt{6}}{-1})

(= \frac{7}{-1} - \frac{3\sqrt{6}}{-1})

(= -7 + 3\sqrt{6})

(= 3\sqrt{6}-7)

( = log_2 \frac{8 \times 16}{4})

( = log_2 32)

( = log_2 2^5)

( = 5log_2 2)

( = 5 \times 1)

( = 5 )

Q = (P (\cup) Q) - P

{6,7}

gt² - k - w = 0

gt² = k + w

(g = \frac{k + w}{t^2})