2016 - JAMB Mathematics Past Questions and Answers - page 1

\(\int\) \(\frac{2x^3 + 2x}{x}\) = \(\int\) \(\frac{2x^3}{x}\) + \(\frac{2x}{x}\) = \(\int\) (2x² + 2) dx

\(\frac{2x^2+1}{2 + 1}\) + 2x + k

= \(\frac{2x^3}{3}\)+ 2x + k

\(\frac{4 + y + 8 + 10}{4}\) = 7

22 + y = 4 x 7
22 + y = 28
y = 28 - 22 = 6

Y = ( \(\frac{1}{3}\)X + 6)²

\(\frac{dy}{dx}\) = 2( \(\frac{1}{3}\)X + 6) \(\frac{1}{3}\)

= \(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)

80 - x + x + 60 - x + 20 = 150
160 - x = 150
x = 160 - 150 = 10

T₂ = \(\frac{8}{9}\), T₆ = 4\(\frac{1}{2}\)
ar = \(\frac{8}{9}\)
ar⁵ = \(\frac{9}{2}\)

\(\frac{ar}{ar^5}\) = \(\frac{8}{9}\) x \(\frac{2}{9}\)

\(\frac{1}{r^4}\) = \(\frac{16}{81}\)

r = \(\sqrt[4]{18/16}\) = \(\frac{3}{2}\)

< OTQ = \(\frac{130}{2}\)
= 65^o

\(\frac{(n - 2) 180}{180}\) = \(\frac{1080}{180}\)

(n - 2) = 6
n = 6 + 2 = 8

< MPT = 180^o - 118^o = 62^o

< PML = 62^o ( Alternative angle)

y + 2y + 10^o + 62^o = 180^o (Angles on a straight line)

3y = 180 - 72
\(\frac{3y}{3}\) = \(\frac{108}{3}\)
y = 36^o

< PMT = 2y + 10 = 2(36) + 10 = 82^o

< ROP = 95^o (Exterior angle of cyclic quadrilateral)

Number of students that plays only two games = 4 + 8 + 3 + = 15