2016 - JAMB Mathematics Past Questions and Answers - page 1

(\int) (\frac{2x^3 + 2x}{x}) = (\int) (\frac{2x^3}{x}) + (\frac{2x}{x}) = (\int) (2x² + 2) dx

(\frac{2x^2+1}{2 + 1}) + 2x + k

= (\frac{2x^3}{3})+ 2x + k

(\frac{4 + y + 8 + 10}{4}) = 7

22 + y = 4 x 7

22 + y = 28

y = 28 - 22 = 6

Y = ( (\frac{1}{3})X + 6)²

(\frac{dy}{dx}) = 2( (\frac{1}{3})X + 6) (\frac{1}{3})

= (\frac{2}{3}) ( (\frac{1}{3})X + 6)

80 - x + x + 60 - x + 20 = 150

160 - x = 150

x = 160 - 150 = 10

T₂ = (\frac{8}{9}), T₆ = 4(\frac{1}{2})

ar = (\frac{8}{9})

ar⁵ = (\frac{9}{2})

(\frac{ar}{ar^5}) = (\frac{8}{9}) x (\frac{2}{9})

(\frac{1}{r^4}) = (\frac{16}{81})

r = (\sqrt[4]{18/16}) = (\frac{3}{2})

< OTQ = (\frac{130}{2})

= 65^o

(\frac{(n - 2) 180}{180}) = (\frac{1080}{180})

(n - 2) = 6

n = 6 + 2 = 8

< MPT = 180^o - 118^o = 62^o

< PML = 62^o ( Alternative angle)

y + 2y + 10^o + 62^o = 180^o (Angles on a straight line)

3y = 180 - 72

(\frac{3y}{3}) = (\frac{108}{3})

y = 36^o

< PMT = 2y + 10 = 2(36) + 10 = 82^o

< ROP = 95^o (Exterior angle of cyclic quadrilateral)

Number of students that plays only two games = 4 + 8 + 3 + = 15