2016 - JAMB Mathematics Past Questions and Answers - page 3

(\frac{0.026 \times 0.36}{0.69}) = (\frac{26 \times 10^-3 \times 36 \times 10^-2}{69 \times 10^-2})

= 0.01356 = 1.36 x 10^-2

Let x represent total number of pencils shared

B : S : T

2 : 3 : 5

2+3+5 = 10

(\frac{2}{10}) x x = 5

(\frac{2x}{10}) = 5

2x = 50
x = 25

Perimeter = 2r + (\frac{\theta}{360}) x 2(\pi)r

2(9) + (\frac{36}{360}) x 2 x (\pi) x 9 = 18 + (\frac{9\pi}{5})

(\frac{27^\frac{1}{3} - 8^\frac{2}{3}}{16^\frac{2}{4} \times 2})

(\frac{27^\frac{1}{3} - 8^\frac{2}{3}}{16^\frac{2}{4} \times 2}) = (\frac{3\sqrt{27} - 3\sqrt{8}^2}{\sqrt{16} \times 2})

(\frac{3 - 4}{4 \times 2})

= (\frac{-1}{8})

Mean = (\frac{(2 \times 3) + (3 \times 6) + (4 \times 5) + (2 \times 6)}{2 + 3 + 4 + 6})

= (\frac{6 + 18 + 20 + 12}{15}) = (\frac{56}{15})

= 3.73

y = (\frac{2}{3})x³ - (\frac{4}{x})

(\frac{dy}{dx}) = 2x² - Lx^-2 = 2x² + (\frac{4}{x^2})

(\frac{0.8 \times 0.43 \times 0.031}{0.05 \times 0.72 \times 0.021}) x (\frac{10}{10}) = 14.11

Length or arc = (\frac{\theta}{360}) x 2(\pi)r

= (\frac{30}{360}) x 2 x (\frac{22}{7}) x 12

= (\frac{1}{12}) x 2 x (\pi) x 2 = 2(\pi)cm

(\int\limits_0^\frac{\pi}{2}) sin xdx = -cosx|(\frac{\pi}{2})

= -(cos(\frac{\pi}{2}) - cos0) = -(0-1) = 1

L = (\frac{\theta}{360}) x 2(\pi)r

16(\pi) = (\frac{80}{360}) x 2(\pi)r

(\frac{16\pi \times 360}{80 \times 2\pi}) = r

r = 36cm