2016 - JAMB Mathematics Past Questions and Answers - page 4

Mean = \(\frac{2 - t + 4 + t + 3 - 2t + 2 + t + t - 1}{5}\)

= \(\frac{10}{5}\) = 2

\(\frac{12.02 \times 20.06}{26.04 \times 60.06}\) = \(\frac{241.1212}{15698.96}\) = 0.154

y = 2x³ + 6x² + 6x + 1

\(\frac{dy}{dx}\) = 6x² + 12x + 6

3,9,27,81,.....
r = \(\frac{9}{8}\) = 3
T_n = ar^n-1

T_n = 3(3)^n-1 = \(\frac{3(3^2)}{3}\)

1 - (\(\frac{1}{7}\) x 3 \(\frac{1}{2}\)) \(\div\) \(\frac{3}{4}\)

1 - (\(\frac{1}{7}\) x \(\frac{7}{2}\)) x \(\frac{4}{3}\)

1 - \(\frac{1}{2}\) x \(\frac{4}{3}\)

1 - \(\frac{2}{3}\) = \(\frac{1}{3}\)

120km \(\to\) 45litres
1km \(\to\) \(\frac{45}{120}\)litres
600km \(\to\) \(\frac{45}{120}\) x 600 = 225litres

y = 3x³ + 2x² + 3x + 1
\(\frac{dy}{dx}\) = 9x² + 4x + 3

\(\int\)^{(sin x - 5x^2)} = -cosx - \(\frac{5x^3}{3}\) + k

N = \(\frac{p}{2}\)(\(\frac{T_1 - T_2}{T_1}\))
12 = \(\frac{p}{2}\)(\(\frac{27 - 24}{27}\))
24 = P(\(frac{3}{27}\)
P = 24 x 9 = 216

3x - 5y = 9 ------x2
6x - 4y = 12 -----x1
6x - 10y = 18
-6x - 4y = 12
____________
\(\frac{6y}{-6}\) = \(\frac{6}{6}\)

y = -1
in eq (1) 3x - 5y = 9
3x - 5(-1) = 9
3x + 5 = 9
3x = 4
x = \(\frac{4}{3}\)