2018 - JAMB Mathematics Past Questions and Answers - page 2

11

A school girl spends \(\frac{1}{4}\) of her pocket money on books and \(\frac{1}{3}\) on dress. What fraction remains?

A
\(\frac{5}{6}\)
B
\(\frac{7}{12}\)
C
\(\frac{5}{12}\)
D
\(\frac{1}{6}\)
correct option: c
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12

 

If \(\frac{x}{a + 1}\) + \(\frac{y}{b}\) = 1. Make y the subject of the relation.

A
\(\frac{b(a + 1 - x)}{a + 1}\)
B
\(\frac{a + 1}{b(a - x + 1)}\)
C
\(\frac{a(b - x + 1)}{b + 1}\)
D
\(\frac{b}{a(b - x + 1)}\)
correct option: a
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13

Calculate the total surface area of a cupboard which measures 12cm by 10cm by 8cm

A
1920cm\(^2\)
B
592cm\(^2\)
C
296cm\(^2\)
D
148cm\(^2\)
correct option: b

Total surface area of a cupboard, A = 2(lb + bh + lh) L = 12, b = 10, h = 8

  A = 2((12 x 10) + (10 x 8) + (12 x 8))

  A = 2(120 + 80 + 96)

  A = 2 x 296

  A = 592cm\(^2\)

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14

Convert 0.04945 to two significant figures

A
0.040
B
0.049
C
0.050
D
0.49
correct option: c
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15

From a point R, 300m north of P, a man walks eastward to a place Q which is 600m from P. Find the bearing of P from Q, correct to the nearest degree

A
026°
B
045°
C
210°
D
240°
correct option: d
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16

The probabilities that John and James pass an examination are \(\frac {3}{4}\)and \(\frac {3}{5}\) respectively. Find the probability of both boys failing the examination.

 

A
\(\frac {1}{10}\)
B
\(\frac {2}{10}\)
C
\(\frac {9}{20}\)
D
\(\frac {11}{20}\)
correct option: d

Probability (both John and James passed):

  = \(\frac {3}{4}\) x \(\frac {3}{5}\)

  = \(\frac {9}{20}\)

  Pr(john and james failed)= 1- Pr(john and james passed)

  = 1 – \(\frac {9}{20}\)

  = \(\frac {11}{20}\)

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17

An arc of a circle of radius 14cm subtends angle 300° at the centre. Find the perimeter of the sector formed by the arc (take π = \(\frac{22}{7}\))

A
14.67cm
B
42.67cm
C
101.33cm
D
513.33cm
correct option: c
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18

Simplify

\(\frac {25 \frac{2}{3} +  25 \frac{1}{6}} {(\frac{1}{5}) \frac{7}{6} \times (\frac{1}{5}) \frac{1}{6}}\)

A
25
B
A. \(\frac{1}{5}\)
C
B. 1
D
C. \(\frac{1}{25}\)
correct option: b
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19

Make T the subject of the relation.

A
T = \(\frac{R + P3}{15Q}\)
B
T = \(\frac{R - 15P^3}{Q}\)
C
T =R - \(\frac{15P^3}{Q}\)
D
T = \(\frac{15R + Q}{P^3}\)
correct option: c
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20

What is the place value of 9 in the number 3.0492?

A
\(\frac{9}{10000}\)
B
\(\frac{9}{1000}\)
C
\(\frac{9}{100}\)
D
\(\frac{9}{10}\)
correct option: b
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