2018 - JAMB Mathematics Past Questions and Answers - page 7

A1 = Elements in the universal set but not in A = {s, w, x, y, z}

  B = {r, s. t, u}

  C = {t, u, v, w, x}

  A1 n B n C = elements common to the three sets = none = empty set = Φ

Taking the cube of both sides of the equation give

  P\(^3\) = \(\frac{Q(R - T)}{15}\)

  Cross multiplying

  15P\(^3\) = Q(R - T)

  Divide both sides by Q

  \(\frac{15P^3}{Q}\) = R - T

  Rearranging gives

  T = R - \(\frac{15P^3}{ Q}\)

  = \(\frac{RQ - 15P^3}{Q}\)

  Answer is C

An equilateral triangle has all sides equal and of the angles equal as 60 degrees each

  Area = \(\frac{1}{2}\) absinθ

  Area = \(\frac{1}{2}\) x 8 x 8 x sin60

  = \(\frac{1}{2}\) x 64 x \(\sqrt{\frac{3}{2}}\)

  = 16√3 cm\(^2\)

Let the monthly expenditure angle for school fees is x,
This implies that housing will be 2x.
Recall that angle in the circle is 360.

  Using 90 as the angle for transport,

  x + 2x + 120 + 90 = 360

  3x + 210 = 3605

  3x = 360 - 210

  = 150

  x = \(\frac{150}{3}\) = 50

  So the angle for housing is 2x = 2 × 50

  = 100

  Amount spent on housing = \(\frac{100}{360}\) × 7200

  = ₦2000

Applying law of indices

25\(\frac{1}{2}\) × 8\(\frac{-2}{3}\)

  = √25 x (\(\sqrt[3]{8}\)) -2

  = 5 x 2-2

  = 5 x \(\frac{1}{2^2}\) =

 \(\frac{5}{4}\) = \(\frac{11}{4}\)