2018 - JAMB Mathematics Past Questions and Answers - page 4

31

\(\frac{0.00256 \times 0.0064}{0.025 \times 0.08}\)

A
8.8 x 10\(^{-1}\)
B
8.8 x 10\(^{-2}\)
C
8.8 x 10\(^{-3}\)
D
8.8 x 10\(^{3}\)
correct option: c
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32

Two sisters, Taiwo and Kehinde, own a store. The ratio of Taiwo's share to Kehinde's is 11:9. Later Kehinde sells \(\frac{2}{3}\) of her share to Taiwo for N720.00. Find the value of the store

A
N1,080.00
B
N2,400.00
C
N3,000.00
D
N3,600.00
correct option: b
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33

A room is 12m long, 9m wide and 8m high. Find the cosine of the angle which a diagonal of the room makes with the floor of the room

A
\(\frac{15}{17}\)
B
\(\frac{9}{17}\)
C
\(\frac{8}{15}\)
D
\(\frac{12}{17}\)
correct option: a
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34

Divide the L.C.M of 48, 64 and 80 by their H.C.F

A
20
B
30
C
48
D
60
correct option: d
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35

Find the equation of the line through (5,7) parallel to the line 7x + 5y = 12 

A
5x + 7y = 20
B
7x + 5y = 70
C
xy = 7
D
15x + 17y = 90
correct option: b
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36

A man's initial salary is N540.00 a month and increases after each period of six months by N36.00 a month. Find his salary in the eight month of the third year.

A
N828.00
B
N756.00
C
N720.00
D
N684.00
correct option: c

Give that the salary increases by 36 after every 6 months

  then every 6 months that can be counted on the eight month of the third year is 5

  (i.e. 2 times in the first year, 2 times in the second year and once in the third year)

  His salary then = initial salary + increment

  = 540 + 5(36)

  = 540 + 180

  = ₦720.00

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37

A man stands on a tree 150cm high and sees a boat at an angle of depression of 74°. Find the distance of the boat from the base of the tree.

A
52cm
B
43cm
C
40cm
D
15cm
correct option: b

Tan 74 = 150/x

  x = 150/tan 74

  = 43.01cm

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38

Integrate the expression 6x\(^2\) - 2x + 1

A
3x\(^3\) - 2x\(^2\) + x + c
B
2x\(^3\) - x\(^2\) + x + c
C
2x\(^3\) – 3x\(^2\) + c
D
x\(^3\) + x\(^2\) – x + c
correct option: b
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39

In how many ways can the letters LEADER be arranged?

A
72
B
144
C
360
D
720
correct option: c

In the given word LEADER are 1L 2E 1A 1D and 1R making total of 6! \(\frac{6}{1!2!1!1!1!}\) = \(\frac{6!}{2!}\)

  = \(\frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1}\)

  = 360

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40

In the figure shown, /MX/ = 8cm, /XN/ = 12cm, /NZ/ = 4cm and ∠ XMN = ∠ XZY. Calculate /YM/

 

A
32cm
B
24 cm
C
16 cm
D
12 cm
correct option: c

From the figure,

  ∠ XMN = ∠ XZY

  Angle X is common

  So, ∠ XNM = ∠ XYZ

  Then from the angle relationship

  \(\frac{XM}{XZ}\) = \(\frac{XN}{XY}\) = \(\frac{MN}{ZY}\)

  XM = 8, XZ = 12 + 4 = 16,

  XN = 12, XY = 8 + YM

  \(\frac{8}{16}\) = \(\frac{12}{(8 + YM) }\)

  Cross multiply

  8(8 + YM) = 192

  64 + 8YM = 192

  8YM = 128

  YM = \(\frac{128}{8}\)

  = 16cm

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