2024 - JAMB Mathematics Past Questions and Answers - page 1
In how many ways can the word MATHEMATICIAN be arranged?
6794800 ways
2664910 ways
6227020800 ways
129729600 ways
Step-by-Step Solution:
Count the total number of letters:
The word "MATHEMATICIAN" has 13 letters.
Identify the frequency of each letter:
- M: 2
- A: 3
- T: 2
- H: 1
- E: 1
- I: 2
- C: 1
- N: 1
Use the formula for permutations of a multiset:
Total permutations = \(\frac{13!}{2! \cdot 3! \cdot 2! \cdot 1! \cdot 1! \cdot 2! \cdot 1!}\)
Plug in the values:
Total permutations = \(\frac{13!}{2! \cdot 3! \cdot 2! \cdot 1! \cdot 1! \cdot 2! \cdot 1!}\)
Total permutations = \(\frac{6227020800}{48} = 129729600\)
The number of ways to arrange the letters in the word MATHEMATICIAN is 129729600.
A room is 12m long, 9m wide and 8m high. Find the cosine of the angle which a diagonal of the room makes with the floor of the room
We are given the equation of two 2x2 determinants:
\(\begin{vmatrix} 5 & 3 \\ x & 2 \end{vmatrix} = \begin{vmatrix} 3 & 5 \\ 4 & 5 \end{vmatrix}\)
First, we calculate the determinant of the left-hand side:
\(\begin{vmatrix} 5 & 3 \\ x & 2 \end{vmatrix} = (5 \times 2) - (3 \times x) = 10 - 3x\)
Now, calculate the determinant of the right-hand side:
\(\begin{vmatrix} 3 & 5 \\ 4 & 5 \end{vmatrix} = (3 \times 5) - (5 \times 4) = 15 - 20 = -5\)
Now, equate both determinants:
10 - 3x = -5
Solve for \(x\):
Subtract 10 from both sides:
-3x = -5 - 10
-3x = -15
Now, divide by -3:
x = \(\frac{-15}{-3} = 5\)
Thus, the value of \(x\) is 5.
The correct option is x = 5.
\(\frac{(2 - \sqrt5)(3 + \sqrt5)}{(3 - \sqrt5)(3 + \sqrt5)}\) = \(\frac{6 +2\sqrt5 - 3\sqrt5 - \sqrt25}{9 + 3\sqrt5 - 3\sqrt5 - \sqrt25}\)
= \(\frac{6 - \sqrt5 - 5}{9 - 5}\)
= \(\frac{1 - \sqrt5}{4}\)
To find the standard deviation, we follow these steps:
- Find the mean of the data: The data set is: 2, 3, 8, 10, 12.
- Find the squared differences from the mean for each data point:
- For 2: \( (2 - 7)^2 = (-5)^2 = 25 \)
- For 3: \( (3 - 7)^2 = (-4)^2 = 16 \)
- For 8: \( (8 - 7)^2 = (1)^2 = 1 \)
- For 10: \( (10 - 7)^2 = (3)^2 = 9 \)
- For 12: \( (12 - 7)^2 = (5)^2 = 25 \)
- Find the variance: The variance \( \sigma^2 \) is the average of the squared differences:
- Find the standard deviation: The standard deviation \( \sigma \) is the square root of the variance:
S.D = \(\sqrt{\frac{(x - \varkappa)^2}{n}}\)
S.D = \(\sqrt{\frac{76}{5}}\)
S.D = 3.9
Therefore, the standard deviation is approximately 3.9.
Let u = 2x + 1 so that, y = u3
\(\frac{dy}{du}\) = 3u2 and \(\frac{dy}{dx}\) = 2
Hence by the chain rule,
\(\frac{dy}{dx}\) = \(\frac{dy}{du}\) x \(\frac{du}{dx}\)
= 3u2 x 2
= 6u2
= 6(2x + 1)2
To solve the quadratic equation \( 3x^2 - 4x - 5 = 0 \), we will use the quadratic formula:
The quadratic formula is given by:
\( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
In the equation \( 3x^2 - 4x - 5 = 0 \), the coefficients are:
- a = 3
- b = -4
- c = -5
Now, substitute the values of \( a \), \( b \), and \( c \) into the quadratic formula:
\( x = \frac{-(-4) \pm \sqrt{(-4)^2 - 4(3)(-5)}}{2(3)} \)
\( x = \frac{4 \pm \sqrt{16 + 60}}{6} \)
\( x = \frac{4 \pm \sqrt{76}}{6} \)
Now, calculate the square root of 76:
\( \sqrt{76} \approx 8.7178 \)
Thus, the equation becomes:
\( x = \frac{4 \pm 8.7178}{6} \)
Now, solve for both values of \( x \):
1) For \( x_1 = \frac{4 + 8.7178}{6} \):
\( x_1 = \frac{12.7178}{6} \approx 2.12 \)
2) For \( x_2 = \frac{4 - 8.7178}{6} \):
\( x_2 = \frac{-4.7178}{6} \approx -0.79 \)
Therefore, the solutions to the equation are \( x = 2.12 \) or \( x = -0.79 \)
To find the volume of a cuboid, we use the formula:
\(\text{Volume} = \text{Length} \times \text{Breadth} \times \text{Height}\)
Given:
- Length = 0.76 cm
- Breadth = 2.6 cm
- Height = 0.82 cm
Now, we calculate the volume:
\(\text{Volume} = 0.76 \times 2.6 \times 0.82\)
Multiplying the values step by step:
\(0.76 \times 2.6 = 1.976\)
\(1.976 \times 0.82 = 1.61952\)
Rounding to two decimal places, we get:
\(\text{Volume} \approx 1.62 \, \text{cm}^3\)
Thus, the correct option is a volume of 1.62 cm³.