Linear Inequalities - JSS2 Mathematics Past Questions and Answers - page 1
Solve the inequality 3๐ฅโ4>2. What is the value of ๐ฅ?
๐ฅ>2
๐ฅ>1
๐ฅ<1
๐ฅโฅ1
Which of the following represents the solution to the inequality ๐ฅ+5โค8?
๐ฅโค2
๐ฅ<2
๐ฅโฅ3
๐ฅ>3
If 2๐ฅโ1โฅ7, which of the following is true?
๐ฅโค3
๐ฅโฅ4
๐ฅ>3
๐ฅ<4
Graphically, how would you represent ๐ฅ<5 on a number line?
Closed circle at 5, shading to the left
Open circle at 5, shading to the left
Closed circle at 5, shading to the right
Open circle at 5, shading to the right
What is the solution to the inequality โ3๐ฅ+6โค9?
๐ฅโฅโ1
๐ฅโคโ1
๐ฅโค1
๐ฅโฅ1
A company needs to produce at least 150 units but no more than 400 units of a product each day. Which inequality represents this situation?
150<๐ฅ<400
150โค๐ฅโค400
150โฅ๐ฅโฅ400
150โค๐ฅ<400
Solving and Graphing 3๐ฅโ4>2
Start with the inequality:3๐ฅโ4>2
- Add 4 to both sides: 3๐ฅ>6
- Divide both sides by 3: ๐ฅ>2
Graphical Representation:
- Draw a number line.
- Place an open circle at ๐ฅ=2 (because 2 is not included).
- Shade the region to the right of 2.
Solving and Graphing ๐ฅ+5โค8
Start with the inequality:
๐ฅ+5โค8
Subtract 5 from both sides:
๐ฅโค3
Graphical Representation:
- Draw a number line.
- Place a closed circle at ๐ฅ=3 (because 3 is included).
- Shade the region to the left of 3.
Solving and Graphing 2๐ฅโ1โฅ7
Start with the inequality: 2๐ฅโ1โฅ7
Add 1 to both sides: 2๐ฅโฅ8
Divide both sides by 2:
๐ฅโฅ4
Graphical Representation:
- Draw a number line.
- Place a closed circle at ๐ฅ=4 (because 4 is included).
- Shade the region to the right of 4.
Solving and Graphing โ3๐ฅ+6โค9
Start with the inequality:
โ3๐ฅ+6โค9
Subtract 6 from both sides:
โ3๐ฅโค3
Divide both sides by -3 and reverse the inequality:
๐ฅโฅโ1
Graphical Representation:
- Draw a number line.
- Place a closed circle at ๐ฅ=โ1(because -1 is included).
- Shade the region to the right of -1.