Courses » JSS3 » JSS3 Mathematics » Mathematics Exam Topics » Addition and Subtraction of Numbers in Base 2 Numerals - Questions and Answers

Addition and Subtraction of Numbers in Base 2 Numerals - JSS3 Mathematics Past Questions and Answers - page 2

11

Divide 1100 by 11. What is the result?

A

100

B

101

C

111

D

110

correct option: a
Users' Answers & Comments
12

What is 1010 divided by 10?

A

101

B

110

C

100

D

111

correct option: b
Users' Answers & Comments
13

Add 101and 110.

    101

  + 110

  -----

  1011

Step-by-step:

1+0=1

0+1=1

1+1=10 (write 0, carry 1)

Write down the carry (1)

101+110=1011

Users' Answers & Comments
14

Add 101, 110, and 011.

    101

  + 110

  -----

   1011

+  011

  -----

   1100

Step-by-step:

 

1+1+1=11 (write 1, carry 1)

0+1+1=10 (write 0, carry 1)

1+1=10 (write 0, carry 1)

Write down the carry (1)

101+110+011=1100

Users' Answers & Comments
15

Subtract 101 from 110.

    110

  - 101

  -----

    001

Step-by-step:

0−1 (borrow 1, becomes 10−1=1)

1−0=1

1−1=0

 

110−101=001

Users' Answers & Comments
16

Subtract 010 and 001 from 111.

First, subtract 010 from 111:

    111

  - 010

  -----

    101

 

Next, subtract 001 from 101:

    101

  - 001

  -----

    100

 

111−010−001=100

Users' Answers & Comments
17

Multiply 10 by 11.

    10

  x 11

  -----

    10    (10 * 1)

+ 10    (10 * 1 shifted one position to the left)

  -----

  110

Step-by-step:

10∗1=10

10∗1=10 (shifted one position to the left)

 

10×11=110

Users' Answers & Comments
18

Divide 1100 by 11.

       100

    ------

11 | 1100

   - 110

    -----

      000

Step-by-step:

11 fits into 1100 starting from the second digit, 

so write 1 and subtract 110 from 1100, getting 000.

 

1100÷11=100

Users' Answers & Comments
Recommended: JSS3 Mathematics Lessons
Please share this, thanks: