Addition and Subtraction of Numbers in Base 2 Numerals - JSS3 Mathematics Past Questions and Answers - page 2
Add 101and 110.
101
+ 110
-----
1011
Step-by-step:
1+0=1
0+1=1
1+1=10 (write 0, carry 1)
Write down the carry (1)
101+110=1011
Add 101, 110, and 011.
101
+ 110
-----
1011
+ 011
-----
1100
Step-by-step:
1+1+1=11 (write 1, carry 1)
0+1+1=10 (write 0, carry 1)
1+1=10 (write 0, carry 1)
Write down the carry (1)
101+110+011=1100
Subtract 101 from 110.
110
- 101
-----
001
Step-by-step:
0−1 (borrow 1, becomes 10−1=1)
1−0=1
1−1=0
110−101=001
Subtract 010 and 001 from 111.
First, subtract 010 from 111:
111
- 010
-----
101
Next, subtract 001 from 101:
101
- 001
-----
100
111−010−001=100
Multiply 10 by 11.
10
x 11
-----
10 (10 * 1)
+ 10 (10 * 1 shifted one position to the left)
-----
110
Step-by-step:
10∗1=10
10∗1=10 (shifted one position to the left)
10×11=110
Divide 1100 by 11.
100
------
11 | 1100
- 110
-----
000
Step-by-step:
11 fits into 1100 starting from the second digit,
so write 1 and subtract 110 from 1100, getting 000.
1100÷11=100