Variations - JSS3 Mathematics Past Questions and Answers - page 1

Given 𝑦=𝑘𝑥, substituting the given values:

9=𝑘⋅6

Solving for 𝑘:

𝑘=9/6=1.5

Now, find 𝑦 when 

x=12:

𝑦=1.5⋅12=18

Given 𝑦=𝑘/𝑥, substituting the given values:

20=𝑘/4

Solving for 𝑘:

𝑘=20⋅4=80

Now, find 𝑦 when 𝑥=5:

𝑦=80/5=16

Given 𝑧=𝑘𝑥𝑦, substituting the given values:

36=𝑘⋅3⋅4

Solving for 𝑘: 𝑘=36/12

=3

Now, find 𝑧 when 𝑥=6 and 𝑦=2:

𝑧=3⋅6⋅2=36