Electromagnetism - SS2 Physics Past Questions and Answers - page 2
Two point charges, q1 = +2 μC and q2 = -4 μC, are placed 10 cm apart. What is the electric field at a point located 5 cm from q1 and 5 cm from q2? (Assume vacuum permittivity is ε0 = 8.85 x 10-12 C2/N m2)
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A parallel plate capacitor with a plate area of 100 cm2 and plate separation of 2 mm is connected to a 12 V battery. What is the electric field between the plates? (Assume vacuum permittivity is ε0 = 8.85 x 10-12 C2/N m2)
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A point charge of +5 μC is located at the origin. What is the electric potential at a point 2 metres away from the charge? (Assume vacuum permittivity is ε0 = 8.85 x 10-12 C2/N m2)
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The capacitance of a parallel plate capacitor depends on:
The area of the plates.
The distance between the plates.
The dielectric material between the plates.
All of the above.
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A capacitor stores energy in the form of:
Electric potential.
Electric current.
Electric field.
Electric resistance.
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The capacitance of a capacitor is directly proportional to:
The area of the plates.
The distance between the plates.
The voltage across the capacitor.
The charge is stored on the plates.
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The time constant of an RC circuit depends on:
The resistance (R) of the circuit.
The capacitance (C) of the capacitor.
The product of resistance (R) and capacitance (C).
The voltage across the capacitor.
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When a dielectric material is inserted between the plates of a capacitor, the capacitance:
Decreases.
Increases.
Remains the same.
Depends on the dielectric constant.
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The energy stored in a capacitor is given by the formula:
E = 1/2CV2.
E = 1/2CV.
E = 1/2Q2.
E = 1/2Q.
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When two capacitors are connected in series, the total capacitance is:
The sum of the individual capacitances.
The reciprocal of the sum of the reciprocals of the individual capacitances.
The average of the individual capacitances.
The product of the individual capacitances.
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