# 1989 - WAEC Mathematics Past Questions and Answers - page 1

**correct option:**c

^{3}+ loga

^{5}- loga

^{6}

^{3}* a

^{5}/a

^{6}) = loga

^{64}

a

^{2}= 64 a = 8

**correct option:**d

ar = 8 .....(1)

ar^{3} = 32 .....(2)

divide (2) by (1)

r^{2} = 4 r = 2 ∴ a = 4

^{n}- 1)/r - 1

^{4}- 1)/2 - 1 = 60

In the diagram above, TPS is a straight line, PQRS is a parallelogram with base QR and height 8cm. |QR| = 6cm and the area of triangle QST is 52cm2. Find the area of ΔQPT

^{2}

^{2}

^{2}

^{2}

**correct option:**b

Area of \(\Delta\)QST = 52cm\(^2\); height = 8cm

b=base length; but A = 1/2 b x h

=52=1/2 x b x 8cm = 104 =8b

b=104/8 = 13cm; ST= 13cm; PS = 6cm

TP = 13 - 6 = 7cm;

area of \(\Delta\)QST = 1/2 b x h

= 1/2 x 7 x 8/1 = 28cm\(^2\)

In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.

^{o}

^{o}

^{o}

^{o}

**correct option:**b

< QSR = 90° (angle in a semi-circle)

\(\therefore\) < SQR = 180° - (90° + 62°)

= 28°

Evaluate, using logarithm tables \(\frac{5.34 \times 67.4}{2.7}\)

**correct option:**c

No | Log |

5.34 | 0.7275 + |

67.4 | 1.8287 |

2.5562 - | |

2.7 | 0.4314 |

Antilog = 133.2 | 2.1248 |

\(\therefore \frac{5.34 \times 67.4}{2.7} = 133.2\)

^{2}

**correct option:**b

^{2};

35 - 7b + 5b - b

^{2}

7(5 - b) + 5(5 - b)

(7 + b)(5 - b)

Evaluate \(\frac{0.009}{0.012}\), leaving your answer in standard form.

^{2}

^{1}

^{-1}

^{-2}

**correct option:**c

\(\frac{0.009}{0.012}\)

=\(\frac{0.009}{0.012}\) = \(\frac{9}{12}\) = 0.75

=\(7.5 \times 10^{-1}\)

^{2}- x - 6

The roots of the equation are

^{2}+ x - 15

**correct option:**b

^{2}+ x - 15; 2x

^{2}+ 6x - 5x - 15

(2x

^{2}+ 6x) - ( 5x + 15)

2x(x + 3) - 5(x + 3)

(2x - 5)(x + 3)

^{o}. If XY = 40m, how high is X above the level of Y?