1997 - WAEC Mathematics Past Questions and Answers - page 4

31

TR is the tangent to the circle PQR with centre O. Find the size of ∠PRT

A
44o
B
46o
C
60o
D
74o
correct option: c

Reflex < POQ = 360° - 148° = 212°

< PRO = 360° - 330° = 30°

But < ORT = 90° \(\implies\) < PRT = 90° - 30° = 60°

Users' Answers & Comments
32

Given that \(\frac{1}{2} \log_{10} P = 1\), find the value of P.

A
104
B
103
C
102
D
101
correct option: c

\(\frac{1}{2} \log_{10} P = 1\)

\(\log_{10} P^{\frac{1}{2}} = 1\)

\(P^{\frac{1}{2}} = 10^{1}\)

\(\implies P = 10^{2}\)

Users' Answers & Comments
33
If two triangles are similar, which of the following is true? Their
A
corresponding sides are equal
B
corresponding angles are equal
C
corresponding altitudes are equal
D
areas are equal
correct option: b
Users' Answers & Comments
34

Which of the following is not necessarily true of a rectangle?

A
The diagonals are equal
B
The diagonals bisect each other
C
The diagonals are perpendicular
D
Each diagonal divides the area of the rectangle equally
correct option: c
Users' Answers & Comments
35
A chord is 5cm from the centre of a circle of diameter 26cm. Find the length of the chord
A
16cm
B
18cm
C
24cm
D
25.51cm
correct option: c
BC = 132 - 52 = 12cm
Users' Answers & Comments
36
The angle of elevation of a point T on a tower from a point U on the horizontal ground is 30o. If TU = 54m, how high is T above the horizontal ground?
A
108m
B
72m
C
46.3m
D
31.2m
correct option: e
sin30 = x/54
x =54 x 1/2
= 27m
Users' Answers & Comments
37

Express the true bearing of 250° as a compass bearing

A
N20oE
B
S20oE
C
N20oW
D
S70oW
correct option: d

250° = S 70° W

Users' Answers & Comments
38

lf sin θ= \(\frac{-1}{2}\), find all the values of θ between 0° and 360°.

A
120o,240o
B
120o180o
C
210o,300o
D
210o,330o
correct option: d
Users' Answers & Comments
39
Cos 65o has the same value as
A
Sin 65o
B
Cos 25o
C
Cos 115o
D
Cos 205o
correct option: e
Users' Answers & Comments
40

Two sides of a triangle are perpendicular. If the two sides are 8cm and 6cm, calculate correct to the nearest degree, the smallest angle of the triangle.

A
35o
B
36o
C
37o
D
38o
correct option: c

tanθ = 6/8 = 0.75

θ = tan\(^{-1}\) (0.75)

= 37°

Users' Answers & Comments
Please share this, thanks: