2003 - WAEC Mathematics Past Questions and Answers - page 4

31

If \(P = \sqrt{QR\left(1+\frac{3t}{R}\right)}\), make R the subject of the formula.

A
\(R = \frac{3Qt}{P^2 - Q}\)
B
\(R = \frac{P^2 – 3t}{Q+1}\)
C
\(R = \frac{P^2 + 3t}{Q - 1}\)
D
\(R = \frac{P^2-3Qt}{Q}\)
correct option: d
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32

From the Venn diagram below, how many elements are in P∩Q?

A
1
B
2
C
4
D
6
correct option: b

P \(\cap\) Q = {f, e} = 2

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33

From the Venn Diagram below, find Q' ∩ R.

A
(e)
B
(c, h)
C
(c, g, h)
D
(c, e, g, h)
correct option: c

Q' ∩ R
Q' = U - Q
Q' = {a, b, c, d, g, h, i}
R = {c, e, h, g}
Q' ∩ R = {c, h, g}

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34

The square root of a number is 2k. What is half of the number

A
\(\sqrt{\frac{k}{2}}\)
B
\(\sqrt{k}\)
C
\(\frac{1}{2}k^2\)
D
2k2
correct option: d

Let the number be x.

\(\sqrt{x} = 2k \implies x = (2k)^2\)

= \(4k^2\)

\(\frac{1}{2} \times 4k^2 = 2k^2\)

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35

Given that p varies as the square of q and q varies inversely as the square root of r. How does p vary with r?

A
p varies as the square of r
B
p varies as the square root of r
C
p varies inversely as the square of r
D
p varies inversely as r
correct option: d

\(p \propto q^2\)

\(q \propto \frac{1}{\sqrt{r}\)

\(p = kq^2\)

\(q = \frac{c}{\sqrt{r}}\)

where c and k are constants.

\(q^2 = \frac{c^2}{r}\)

\(p = \frac{kc^2}{r}\)

If k and c are constants, then kc\(^2\) is also a constant, say z.

\(p = \frac{z}{r}\)

p varies inversely as r.

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36
The probabilities of a boy passing English and Mathematics test are x and y respectively. Find the probability of the boy failing both tests
A
1-(x-y)+xy
B
1-(x+y)-xy
C
1-(x+y)+xy
D
1 - (x - y) + x
correct option: c
Prob (passing English) = x
Prob (passing Maths) = Y
Prob (failing English) = 1 - x
Prob (failing Maths) = 1 - y
Prob (failing both test) = Prob(failing English) and Prob(failing Maths) = (1 - x)(1 - y)
=1 - y - x + xy
=1 - (y + x) + xy
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37
The locus of points equidistant from two intersecting straight lines PQ and PR is
A
a circle centre P radius Q.
B
a circle centre P radius PR
C
the point of intersection of the perpendicular bisectors of PQ and PR
D
the bisector of angle QPR
correct option: c
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38

Find the equation whose roots are \(-\frac{2}{3}\) and 3

A
3x2+11x-6=0
B
3x2+7x+6=0
C
3x2-11x-6=0
D
3x2-7x-6=0
correct option: d

\(x = -\frac{2}{3} \implies x + \frac{2}{3} = 0\)

\(x = 3 \implies x - 3 = 0\)

\(\implies (x - 3)(x + \frac{2}{3}) = 0\)

\(x^2 - 3x + \frac{2}{3}x - 2 = 0\)

\(x^2 - \frac{7}{3}x - 2 = 0\)

\(3x^2 - 7x - 6 = 0\)

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39
Evaluate Cos 45o Cos 30o - Sin 45o Sin 30o leaving the answer in surd form
A
\(\frac{\sqrt{2}-1}{2}\)
B
\(\frac{\sqrt{3}-\sqrt{2}}{4}\)
C
\(\frac{\sqrt{6}-\sqrt{2}}{2}\)
D
\(\frac{\sqrt{6}-\sqrt{2}}{4}\)
correct option: d
\(cos45^o \times cos30^o - sin45^o \times sin30^o\
\frac{1}{\sqrt{2}}\times \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}}\times \frac{1}{2}\
\frac{\sqrt{3}}{2\sqrt{2}}-\frac{1}{2\sqrt{2}}; = \frac{\sqrt{3}-1}{2\sqrt{2}}=\frac{\sqrt{6}-\sqrt{2}}{4}\)
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40

In constructing an angle, Olu draws line OX. With centre O and a convenient radius, he draws an arc intersecting OX at P. With centre P and the same radius, he draws an arc intersecting the first arc at Q and finally joins OQ. What is the size of angle POQ so constructed?

A
90o
B
75o
C
60o
D
45o
correct option: c
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