2004 - WAEC Mathematics Past Questions and Answers - page 5
X2 - (sum of the roots)x + (product of the roots) = 0
Sum of the roots (= -\frac{1}{2}+\frac{3}{4} = \frac{-2+3}{2}=\frac{1}{4})
Product of the roots = (-\frac{1}{2}\times \frac{3}{4}=\frac{-3}{8}<br />
X^2-\left(\frac{1}{4}\right)x-\frac{3}{8} = 0. Taking \hspace{1mm}the\hspace{1mm} common)
(8x^2-2x-3=0);
(P \propto \frac{1}{\sqrt{r}} P=3\hspace{1mm}r=16<br /> P = \frac{k}{\sqrt{r}}\Rightarrow 3 = \frac{k}{\sqrt{16}}\Rightarrow \frac{3}{1} = \frac{k}{4} \ \Rightarrow K = 12 \Rightarrow K = 12; P\sqrt{r} = k \Rightarrow \sqrt{r} = \frac{k}{p}<br /> r = \frac{(k)^2}{P}=12^2 \div \frac{3}{2}=\left(\frac{12}{1}\times \frac{2}{3}\right)=8^2<br /> r = 64)
Users' Answers & CommentsII Equidistant from two given points P and Q is a circle of radius |PQ|. III Equidistant from two points is the perpendicular bisector of the line joining the two points.
The sides of two cubes are in the ratio 2:5. What is the ratio of their volumes?
The ratio of the two cubes = 2:5
Volume of the two cubes = 2\(^3\) : 5\(^3\) = 8 : 125
3(2)2 - (-5)2 - (-4)3
3(4) – (25) – (-64); 12 – 25 + 64 = 51
The rate of interest charge = 51/2% p.a
The amount borrowed = N125, 000:00
Interest charge (=\frac{11}{200} of N125,000<br />
= 11 \times N625.00 = N6,875.00)
The amount refunded by the member with interest charge by the cooperative society
N125,000+N6,875.00 = N131,875.00
Prob(RW or WR) = Prob(RW) + Prob(WR)
(Prob(R) = \frac{3}{5}:Prob(W) = \frac{2}{5}<br />
Prob(RW\hspace{1mm}or\hspace{1mm}WR)=\frac{3}{5}\times\frac{2}{5}+\frac{2}{5}\times \frac{3}{5}<br />
\frac{6}{25}+\frac{6}{25}=\frac{12}{25})
θ= angle of depression of the point from the top of the wall
(tan\theta = \frac{7}{5}=1.4; \theta = tan^{-1}(1.400)<br />
\theta = 54.4^{\circ}; \theta = 54^{\circ}) to the nearest degree