2006 - WAEC Mathematics Past Questions and Answers - page 3

The roots are -3 and 1

x = -3 and x = 1

y = (x + 3)(x - 1)

= x² - x + 3x - 3

y = x² + x - 6 = 0

log_a270 - log_a10 + log_a\(\frac{1}{3}\) = 2

log_a270 + log_a\(\frac{1}{3}\) - log_a10 = 2

log_a(270\(\frac{\frac{1}{3}}{10}\)) = 2

log_a9 = 2

a^a = 9

a = \(\sqrt{9}\) = 3

Volume = \(\frac{1}{3} \pi r^2h = \frac{1}{3} \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} \times \frac{6}{1}\)

V = \(\frac{6468}{84}\)

= 77cm³

Cubic both sides; P³ = \(\frac{Q(R - T)}{15}\)

(cross multiplication) Q(R - T) = 15P³

(divide both sides by Q); R - T = 15\(\frac{1}{Q}\)

(subtract r from both sides) - T = \(\frac{15P^3}{Q - R}\)

T = R - \(\frac{15P^3}{Q}\)

(1 - \(\frac{20}{100}\)) = cash payment fraction= \(\frac{4}{5}\)

The ratio of the cash payment to the marked price = 4:5

radius = \(\frac{diameter}{2}\) = \(\frac{1.4}{2}\)

= 0.7m

circumference = 2\(\pi r = 2 \times \frac{22}{7} \times 0.7m = 4.4m\)

distance covered = 4.4m x 100 = 440m

P¹ = {2, 4, 6, 8, 10}; {1, 3, 5, 7, 9}

P¹ \(\cap\) q¹ = {} or \(\varnothing\)

(3y - 450 + (y + 25) + t = 360^o(angles at a point)

3y - 45 + y + 25 + y = 360

5y = 360 + 20

5y = 380

y = \(\frac{380}{5}\)

= 76^o

Area of carpet = 2.5 x 2.4 = 6

Let F represent the floor

6 = 5% of F

6 = \(\frac{5}{100}\) x F

5F = 6 x 100

F = 6 x \(\frac{100}{5}\)

= 120m²